1. Belajar
  2. Nota Ringkas
  3. Senarai
  4. Membahagi perpuluhan dengan perpuluhan, hasilnya hingga tiga tempat perpuluhan
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Perpuluhan

3.1  Darab dan Bahagi Perpuluhan

 Situasi 1

LANGKAH 1 LANGKAH 2
\(\space\space\space\space\small{\color{red}1}\\ \space\space\space1\,\space.\space5\space l\\ \underline{\times\space\space\space\space\space2\space\space}\\ \underline{\space\space\space3\,\space.\space0\space l}\\\) \(\begin{aligned}\color{red}{\space0\space.\space3\space7\space5\space l} \\8\space\overline{)3\space.\space0\space0\space0\space l} \\\underline{-\space0}\space\space\space\space\space\space\quad\space\space\space \\3\space\space\space0\quad\quad \\\underline{-\space2\space\space\space4}\space\quad\space\space\space \\ \space6\space0\quad\space\\\underline{-\space\space5\space6}\space\space\space\space\space \\\space4\space0\space\space \\\underline{-\space4\space0}\space\space \\\color{green}{0\space\space} \end{aligned}\)

                                 

 Situasi 2

\(36.27\times5.9\div13=\)

STEP 1 STEP 2
\(\quad\space\small{\color{red}3}\space\small{\color{red}1}\space\space\space\small{\color{red}3}\space\space\\ \quad\space\small{\color{red}5}\space\small{\color{red}2}\space\space\space\small{\color{red}6}\space\\ \space\space\space\space\quad\space3\space6\space.2\,\space7\\ \underline{\times\space\space\quad\space\quad\space\space5\space.9}\\ \small{\color{red}1}\quad\quad\quad\quad\\ \space\space\space\space\space\space3\space2\space6\space\space4\space\space3\\ \underline{+1\space8\space1\space3\space\space5\space\space0}\\\underline{\space\space\space2\space1\space3.9\space\space9\space\space3}\\\) \(\begin{aligned}\color{red}{\space1\space6\space.\space4\space6\space1} \\13\space\overline{)2\space1\space3\space.\space9\space9\space3} \\\underline{-\space1\space3}\space\quad\quad\quad \\8\space3\quad\space\space\quad \\\underline{-\space7\space8}\quad\quad\space\space \\ \space5\space9\quad\space\space\space\\\underline{-\space\space5\space2}\quad\space\space\space \\\space7\space9\quad \\\underline{-\space7\space8}\quad\\\ \space1\space3\space\\\underline{-\space1\space3}\space\\\color{green}{0\space} \end{aligned}\)

                                                 
 
3.2  Selesaikan Masalah

 Situasi 1

 Terdapat 25 peket gula yang mempunyai jisim yang sama di dalam sebuah bekas. Campuran kesemua peket itu berjisim 0.125 kg. Hitung jisim, dalam kg, bagi 1.5 peket gula itu.     

Penyelesaian:

\(0.125\ kg\div25\times15=\)

LANGKAH 1 LANGKAH 2
\(\begin{aligned}\color{red}{\space0\space.\space0\space0\space5\space kg} \\25\space\overline{)0\space.\space1\space2\space5\space kg} \\\underline{-\space0}\space\quad\space\quad\quad\space \\0\space\space\space1\quad\quad\space\space \\\underline{-\space\space\space\space0}\space\quad\quad\space \\ \space1\space2\quad\space\space\space\\\underline{-\space\space\space0}\space\quad\space\space\\\space1\space2\space5\space \\\underline{-\space1\space2\space5}\space\\\color{green}{0\space} \end{aligned}\) \(\quad\quad\quad\space\small{\color{red}2}\\ \space\space\space\space\space\space0\space.\space0\space0\space5\space kg\\ \underline{\times\quad\space\space\quad\space1\space5\space\space\space\space}\\ \space\space\space\space\space\space0\space\space\space\space0\space2\space5\\ \underline{+\space0\space0\space\space\space0\space5\space0\space\space\space\space}\\ \underline{\quad\space\space0\space.\space0\space7\space5\space kg}\\\)

 

Situasi 2

 Panjang cermin tingkap di bilik Amin ialah 1.2 m dan lebarnya 1.14 m. Cermin tingkap ini terdiri daripada dua bahagian cermin yang sama saiz. Bahagian cermin di sebelah kanan telah pecah dan perlu diganti. Hitung luas, dalam m², bahagian cermin yang pecah itu.

Penyelesaian:

\(1.2\ m\times1.14\ m\div2=\)

LANGKAH 1 LANGKAH 2
\(\begin{aligned}\space\space\space\space\space\space\space1\space.\space1\space\space4\space m\\ \underline{\times\space\space\space\space\space\space\space\space\space1\space.2\space m}\\ \space\space2\space\space\space\space2\space\space8\space\space\space\space\\ \underline{+\space\space1\space1\space\space\space\space4\space\space0\quad}\\ \underline{\space\space\space\space\space1.3\space\space\space6\space\space8\space m^2} \end{aligned}\\\) \(\begin{aligned}\color{red}{\space0\space.\space6\space8\space4\space m^2} \\2\space\overline{)1\space.\space3\space6\space8\space m^2} \\\underline{-\space0}\space\quad\space\quad\quad\space \\1\space\space\space3\quad\quad\space\space \\\underline{-\space1\space\space\space2}\space\quad\quad\space \\ \space1\space6\quad\space\space\space\\\underline{-\space1\space6}\space\quad\space\space\\\space0\space8\space\space\space\space \\\underline{-\space\space8}\space\space\space\space\\\color{green}{0\space\space\space\space} \end{aligned}\)

 
Pandangan yang dinyatakan dalam Nota ini adalah dari pemilik kandungan Eksperimen.

Perpuluhan

3.1  Darab dan Bahagi Perpuluhan

 Situasi 1

LANGKAH 1 LANGKAH 2
\(\space\space\space\space\small{\color{red}1}\\ \space\space\space1\,\space.\space5\space l\\ \underline{\times\space\space\space\space\space2\space\space}\\ \underline{\space\space\space3\,\space.\space0\space l}\\\) \(\begin{aligned}\color{red}{\space0\space.\space3\space7\space5\space l} \\8\space\overline{)3\space.\space0\space0\space0\space l} \\\underline{-\space0}\space\space\space\space\space\space\quad\space\space\space \\3\space\space\space0\quad\quad \\\underline{-\space2\space\space\space4}\space\quad\space\space\space \\ \space6\space0\quad\space\\\underline{-\space\space5\space6}\space\space\space\space\space \\\space4\space0\space\space \\\underline{-\space4\space0}\space\space \\\color{green}{0\space\space} \end{aligned}\)

                                 

 Situasi 2

\(36.27\times5.9\div13=\)

STEP 1 STEP 2
\(\quad\space\small{\color{red}3}\space\small{\color{red}1}\space\space\space\small{\color{red}3}\space\space\\ \quad\space\small{\color{red}5}\space\small{\color{red}2}\space\space\space\small{\color{red}6}\space\\ \space\space\space\space\quad\space3\space6\space.2\,\space7\\ \underline{\times\space\space\quad\space\quad\space\space5\space.9}\\ \small{\color{red}1}\quad\quad\quad\quad\\ \space\space\space\space\space\space3\space2\space6\space\space4\space\space3\\ \underline{+1\space8\space1\space3\space\space5\space\space0}\\\underline{\space\space\space2\space1\space3.9\space\space9\space\space3}\\\) \(\begin{aligned}\color{red}{\space1\space6\space.\space4\space6\space1} \\13\space\overline{)2\space1\space3\space.\space9\space9\space3} \\\underline{-\space1\space3}\space\quad\quad\quad \\8\space3\quad\space\space\quad \\\underline{-\space7\space8}\quad\quad\space\space \\ \space5\space9\quad\space\space\space\\\underline{-\space\space5\space2}\quad\space\space\space \\\space7\space9\quad \\\underline{-\space7\space8}\quad\\\ \space1\space3\space\\\underline{-\space1\space3}\space\\\color{green}{0\space} \end{aligned}\)

                                                 
 
3.2  Selesaikan Masalah

 Situasi 1

 Terdapat 25 peket gula yang mempunyai jisim yang sama di dalam sebuah bekas. Campuran kesemua peket itu berjisim 0.125 kg. Hitung jisim, dalam kg, bagi 1.5 peket gula itu.     

Penyelesaian:

\(0.125\ kg\div25\times15=\)

LANGKAH 1 LANGKAH 2
\(\begin{aligned}\color{red}{\space0\space.\space0\space0\space5\space kg} \\25\space\overline{)0\space.\space1\space2\space5\space kg} \\\underline{-\space0}\space\quad\space\quad\quad\space \\0\space\space\space1\quad\quad\space\space \\\underline{-\space\space\space\space0}\space\quad\quad\space \\ \space1\space2\quad\space\space\space\\\underline{-\space\space\space0}\space\quad\space\space\\\space1\space2\space5\space \\\underline{-\space1\space2\space5}\space\\\color{green}{0\space} \end{aligned}\) \(\quad\quad\quad\space\small{\color{red}2}\\ \space\space\space\space\space\space0\space.\space0\space0\space5\space kg\\ \underline{\times\quad\space\space\quad\space1\space5\space\space\space\space}\\ \space\space\space\space\space\space0\space\space\space\space0\space2\space5\\ \underline{+\space0\space0\space\space\space0\space5\space0\space\space\space\space}\\ \underline{\quad\space\space0\space.\space0\space7\space5\space kg}\\\)

 

Situasi 2

 Panjang cermin tingkap di bilik Amin ialah 1.2 m dan lebarnya 1.14 m. Cermin tingkap ini terdiri daripada dua bahagian cermin yang sama saiz. Bahagian cermin di sebelah kanan telah pecah dan perlu diganti. Hitung luas, dalam m², bahagian cermin yang pecah itu.

Penyelesaian:

\(1.2\ m\times1.14\ m\div2=\)

LANGKAH 1 LANGKAH 2
\(\begin{aligned}\space\space\space\space\space\space\space1\space.\space1\space\space4\space m\\ \underline{\times\space\space\space\space\space\space\space\space\space1\space.2\space m}\\ \space\space2\space\space\space\space2\space\space8\space\space\space\space\\ \underline{+\space\space1\space1\space\space\space\space4\space\space0\quad}\\ \underline{\space\space\space\space\space1.3\space\space\space6\space\space8\space m^2} \end{aligned}\\\) \(\begin{aligned}\color{red}{\space0\space.\space6\space8\space4\space m^2} \\2\space\overline{)1\space.\space3\space6\space8\space m^2} \\\underline{-\space0}\space\quad\space\quad\quad\space \\1\space\space\space3\quad\quad\space\space \\\underline{-\space1\space\space\space2}\space\quad\quad\space \\ \space1\space6\quad\space\space\space\\\underline{-\space1\space6}\space\quad\space\space\\\space0\space8\space\space\space\space \\\underline{-\space\space8}\space\space\space\space\\\color{green}{0\space\space\space\space} \end{aligned}\)

 
Pandangan yang dinyatakan dalam Nota ini adalah dari pemilik kandungan Eksperimen.
Bab : Pecahan, Perpuluhan Dan Peratus
Topik : Membahagi perpuluhan dengan perpuluhan, hasilnya hingga tiga tempat perpuluhan
Tahun 6 Matematik
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