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Dapat menghuraikan garam kalsium sulfat kering dalam makmal.
Contoh jawapan / Sample answer:
P1: Masukkan serbuk kalsium karbonat secara berlebihan ke dalam [\({50}\) - \({100}\) \(\text{cm}^{3}\)] daripada [\({0.5}\) – \({1.0}\) \(\text{mol dm}^{-3}\)] larutan asid hidroklorik / Add calcium carbonate powder in excess into [\({50}\) - \({100}\) \(\text{cm}^{3}\)] of [\({0.5}\) – \({1.0}\) \(\text{mol dm}^{-3}\)] hydrochloric acid solution
P2: Tapis baki kalsium karbonat / Filter the residue of calcium carbonate
P3: Formula bahan tindak balas dan produk yang betul / Correct formulae of reactants and products
P4: Persamaan seimbang \(CaCO_3\) + \(2HCl\) → \(CaCl_2\) + \(H_2O\) + \(CO_2\) / Balanced equation \(CaCO_3\) + \(2HCl\) → \(CaCl_2\) + \(H_2O\) + \(CO_2\)
P5: Tuangkan [\({50}\) - \({100}\) \(\text{cm}^{3}\)] larutan penapisan / kalsium klorida ke dalam bikar / Pour [\({50}\) - \({100}\) \(\text{cm}^{3}\)] of filtrate / calcium chloride solution into a beaker
P6: Masukkan [\({50}\) - \({100}\) \(\text{cm}^{3}\)] daripada [\({0.5}\) – \({1.0}\) \(\text{mol dm}^{-3}\)] [magnesium] larutan sulfat ke dalam bikar. [betul iaitu larutan sulfat] / Add [\({50}\) - \({100}\) \(\text{cm}^{3}\)] of [\({0.5}\) – \({1.0}\) \(\text{mol dm}^{-3}\)] [magnesium] sulphate solution into the beaker. [correct namely sulphate solution]
P7: Tapis dan bilas / Filter and rinse
P8: Keringkan / tekan antara kertas penapis / Dry/ press between filter papers
P9: Formula bahan tindak balas dan produk yang betul / Correct formulae of reactants and products
P10: Persamaan seimbang \(Ca_Cl_2\) + \(MgSO_4\) → \(MgCl_2\) + \(CaSO_4\) / Balanced equation \(Ca_Cl_2\) + \(MgSO_4\) → \(MgCl_2\) + \(CaSO_4\)
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