The following diagram shows that \(EFGH\) is a rectangle drawn on a Cartesian plane.
\(M\) is the midpoint of \(EH.\)
State the coordinate of \(G\).
Given that midpoint \(EH\) is \(M(8,6)\).
\(\begin{aligned} (8,6)&= (\dfrac {2+x} {2} , \dfrac{6+y}{2}) \end{aligned}\)
So, \(H= (14,6)\).
Noted that, \(EH\) is parallel to \(FG\) and \(x\)-axis.
So, the \(x\)-coordinate of \(G\) is \(14\), while the \(y\)-coordinate of \(G\) is \(3\).
Thus, \(G = (14, 3).\)
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