A linear equation that has only one variable and the power of the variable is \(1\).
Subtract \(8\) from a number and its remainder is \( 2\).
The equation is \(x-8=2\).
We can see that it is a linear equation because the equation has one variable, \(x\) and the power of \(x\) is \(1\).
Calculate:
(i) \(3(x+2)=5x\)
(ii) \(\dfrac{x}{6}+3=5\)
(i)
\(\begin{aligned}3(x+2)&=5x \\\\3x+6&=5x \\\\3x+6-6&=5x-6 \\\\3x&=5x-6 \\\\3x-5x&=5x-6-5x \\\\-2x&=-6 \\\\\dfrac{-2x}{-2}&=\dfrac{-6}{-2} \\\\x&=3. \end{aligned}\)
(ii)
\(\begin{aligned}\dfrac{x}{6}+3&=5 \\\\\bigg(\dfrac{x}{6}\times6\bigg)+(3\times6)&=5\times6 \\\\x+18&=30 \\\\x+18-18&=30-18 \\\\x&=12. \end{aligned}\)
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