Find the turning points of the curve
\(y=3x^3-5x^2+4\).
\(\begin{aligned} &(0,4) \\\\ &\text{and}\\\\ &\begin{pmatrix} \dfrac{10}{9},\dfrac{372}{243} \end{pmatrix} \end{aligned}\)
Given that
\(y=x^3-9x^2-5\).
Find the turning points of the curve.
\(\begin{aligned} &(0,-5) \\\\ &\text{and}\\\\ &(6,-123) \end{aligned}\)
The curve
\(y=ax^2+bx+c\)
has a turning point at \((-2,4)\) and passes through the point \((0,12)\).
Find the value of \(a\), of \(b\) and of \(c\).
\(\begin{aligned} a&=2 \\\\ b&=8 \\\\ c&=10 \end{aligned}\)
Given
\(y=3x^2-15x+7\),
find a small change for \(y\) when \(x\) increases from \(2\) to \(2.01\).
\(-0.02\)
\(y=\dfrac{32}{x^5}\),
find the value of \(\dfrac{dy}{dx}\) when \(x=2\).
Hence, estimate the value of \(\dfrac{32}{2.02^5}\).
\(0.75\)
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