Explanation
Answer: |
A |
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The number of particles which is atom can be calculated by multiplying the number of mol with the Avogadro constant.
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The value of the number of moles for the oxygen gas is 2.3 mol.
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\(\text{Number of particles}\\ =\text{Number of mole}\times\text{Avogadro constant}\\ =2.3\,mol \times\,6.02\times10^{23}\,mol^{-1}\\ =1.38\times 10^{24}\)
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The question specifically asks the number of atoms.
In one molecule of oxygen gas, there are two atoms of oxygen.
Thus, the number of particles need to be multiplied by two.
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\(\text{Number of oxygen atoms}\\ =\text{Number of particles}\times2\\ =1.38\times 10^{24}\times 2\\ =2.76\times 10^{24}\)
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The number of oxygen atoms in 2.3 mol of oxygen gas is \(2.76\times 10^{24}\) which is option (A).
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Jawapan: |
A |
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Bagi mendapatkan bilangan zarah iaitu atom bilangan mol perlulah didarab dengan pemalar Avogadro.
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Bilangan mol yang diberi ialah 2.3 mol gas oksigen. |
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\(\text{Bilangan zarah}\\ =\text{Bilangan mol}\times\text{pemalar Avogadro}\\ =2.3\,mol \times\,6.02\times10^{23}\,mol^{-1}\\ =1.38\times 10^{24}\)
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Soalan yang diutarakan adalah berkenaan bilangan atom.
Satu molekul gas oksigen mempunyai 2 atom oksigen.
Oleh itu, bilangan zarah perlu didarab dengan 2.
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\(\text{Bilangan atom oksigen}\\ =\text{Bilangan zarah}\times2\\ =1.38\times 10^{24}\times 2\\ =2.76\times 10^{24}\)
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Bilangan atom oksigen dalam 2.3 mol gas oksigen ialah \(2.76\times 10^{24}\) iaitu pilihan (A).
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Answer: |
A |
|
The number of particles which is atom can be calculated by multiplying the number of mol with the Avogadro constant.
|
|
|
The value of the number of moles for the oxygen gas is 2.3 mol.
|
|
\(\text{Number of particles}\\ =\text{Number of mole}\times\text{Avogadro constant}\\ =2.3\,mol \times\,6.02\times10^{23}\,mol^{-1}\\ =1.38\times 10^{24}\)
|
The question specifically asks the number of atoms.
In one molecule of oxygen gas, there are two atoms of oxygen.
Thus, the number of particles need to be multiplied by two.
|
|
\(\text{Number of oxygen atoms}\\ =\text{Number of particles}\times2\\ =1.38\times 10^{24}\times 2\\ =2.76\times 10^{24}\)
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The number of oxygen atoms in 2.3 mol of oxygen gas is \(2.76\times 10^{24}\) which is option (A).
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