A quadratic function can be expressed in the form \(f(x)=ax^2+bx+c\), where \(a\), \(b\) and \(c\) are constants and \(a \ne 0\).
If \(a\gt 0\), graph has the shape \(\LARGE \smile\) which passes through a minimum point.
If \(a\lt 0\), graph has the shape \(\LARGE \frown\) which passes through a maximum point.
\(b^2-4ac>0\)
\(b^2-4ac=0\)
\(b^2-4ac<0\)
Express quadratic function, \(f(x)=2\left(x+\dfrac{9}{4}\right)^2-\dfrac{1}{8}\) in the intercept form, \(f(x)=a(x-p)(x-q)\), where \(a\), \(p\), and \(q\) are constants and \(p \lt q\). Hence, state the values of \(a\), \(p\), and \(q\).
Convert the vertex form of the quadratic function into the general form first.
\(\begin{aligned} f(x)&=2\left(x+\dfrac{9}{4}\right)^2-\dfrac{1}{8} \\ &=2\left(x^2+\dfrac{9}{2}x+\dfrac{81}{16}\right)-\dfrac{1}{8}\\ &=2x^2+9x+10 \\ &=(2x+5)(x+2)\\ &=2\left(x+\dfrac{5}{2}\right)(x+2). \end{aligned}\)
Thus, the quadratic function in the intercept form for \(f(x)=2\left(x+\dfrac{9}{4}\right)^2-\dfrac{1}{8}\) can be expressed as \(f(x)=2\left(x+\dfrac{5}{2}\right)(x+2)\), where \(a=2\), \(p=-\dfrac{5}{2}\), and \(q=-2\).
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